Comment on page
Set
- Use
Set.addvsMap.set - Use
Set.sizevsArray.length - To remove/delete: use
delete
const new = new Set(old);
Or if enabled:
const new = ...old
for (let value of set.values()) {
...
}
Array.from(new Set())
function setMath<T>(a: Set<T>, b: Set<T>) {
return {
remove: [...a].filter(x => !b.has(x)),
add: [...b].filter(x => !a.has(x)),
};
}
Last modified 4yr ago